Program to find whether a number is Armstrong or not
Definition (Armstrong Number): An n-digit number equal to the sum of the nth powers of its digits.
Example:
153 = 13 + 53 + 33
1634 = 14 + 64 + 34 + 44
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#include<stdio.h> #include<conio.h> #include<math.h> #include<stdlib.h> void main(){ long int num =153, count = 0, i, temp1, temp2, temp3 = 0; clrscr(); printf("Enter the number: "); scanf("%ld",&num); if(num == 0){ printf("\nEnter the number greater than 0"); getch(); exit(0); } temp1 = temp2 = num; while(temp1!=0){ temp1=temp1/10; count++; } for(i=0;i<count;i++){ temp3=temp3 + pow((temp2%10),count); temp2=temp2/10; } if(num == temp3){ printf("\n%ld is an armstrong number",num); } else{ printf("\n%ld is not an armstrong number",num); } getch(); } |
Output:
Enter the number: 92727
92727 is an armstrong number
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Nice share
it can be also written simpler than this. without using and so confusion don’t arrives.
Can u plz tell us different math.h functions you have used.??