This program in C will accept 2 numbers and perform addition of two numbers using call by reference method. The below program accepts 2 numbers from the user and stores the value in num1 and num2. The program then makes a call to add function. We are passing address/reference of num1 and num2 as function parameters and hence the name, call by reference (also known as – pass by reference) #include <stdio.h> #include <stdlib.h> int main(){ int num1, num2, result; /*Accept the numbers from the user*/ printf(“\nEnter the two number: “); scanf(“%d %d”, &num1, &num2); /* Pass the value of...

The below program in C accepts 2 integer numbers and calculates the sum of those 2 numbers using add function. add function accepts two integer parameters namely nos1 and nos2. This function then calculates the sum and return the result to the calling main function. Once the result is received, main function prints the addition of those two numbers #include <stdio.h> #include <stdlib.h> int main(){ int num1, num2, result; /*Accept the numbers from the user*/ printf(“\nEnter the two number: “); scanf(“%d %d”, &num1, &num2); /* Pass the value of num1 and num2 as parameter to function add. The value returned...